if (! ("0123456789"[dval] < '8')) printf("%s failed!\n","\"0123456789\"[dval] < '8'");
 
-The important part here is that the "s in the argument end up being \"s
-in the string, so that it ends up resulting in a string literal whose
-content is the spelling of the argument expression.
+The important part here is that each " in the argument end up being a
+\" in the string, so that it ends up resulting in a string literal
+whose content is the spelling of the argument expression.
 
 I had trouble keeping it straight which of # and ## was which until
 someone pointed out to me that the one with one # is the one that takes
#
#old	
#old		if (! ("0123456789"[dval] < '8')) printf("%s failed!\n","\"0123456789\"[dval] < '8'");
#old	
#old	The important part here is that the "s in the argument end up being \"s
#old	in the string, so that it ends up resulting in a string literal whose
#old	content is the spelling of the argument expression.
#old	
#old	I had trouble keeping it straight which of # and ## was which until
#old	someone pointed out to me that the one with one # is the one that takes
#
#new	
#new		if (! ("0123456789"[dval] < '8')) printf("%s failed!\n","\"0123456789\"[dval] < '8'");
#new	
#new	The important part here is that each " in the argument end up being a
#new	\" in the string, so that it ends up resulting in a string literal
#new	whose content is the spelling of the argument expression.
#new	
#new	I had trouble keeping it straight which of # and ## was which until
#new	someone pointed out to me that the one with one # is the one that takes